1 #include<stdlib.h>
2
3 int main()
4 {
5 int de=1234;
6 float j=45.1234;
7 char ch= ‘s’;
8 double s= 3.1415E+5;
9
10 printf(“de= %d \n”,de);
11 printf(“j= %f\n”,j);
12 printf(“ch= %c \n”,ch);
13 printf(“s= %e \n”,s);
14 return 0;
15
16 }
17
18 /*predicted output
19 *
20 * de= 1234
21 * j= 45.123400
22 * ch= s
23 * s= 3.141500e+05
24 *
25 * ON TERMINAL
26 *
27 * [root@rahulkumar c]# gcc formatprint.c
28 * formatprint.c: In function ‘main’:
29 * formatprint.c:10:3: warning: incompatible implicit declaration of built-in function ‘printf’ [enabled by default]
30 * [root@rahulkumar c]# ./a.out
31 *
32 * OUTPUT
33 *
34 * de= 1234
35 * j= 45.123402
36 * ch= s
37 * s= 3.141500e+05
38 */
39
my question is, if assign or initialise the the value of float variable like above underlined then it take the 22 * ch= s
23 * s= 3.141500e+05
24 *
25 * ON TERMINAL
26 *
27 * [root@rahulkumar c]# gcc formatprint.c
28 * formatprint.c: In function ‘main’:
29 * formatprint.c:10:3: warning: incompatible implicit           declaration of built-in function ‘printf’ [enabled by           default]
30 * [root@rahulkumar c]# ./a.out
31 *
32 * OUTPUT
33 *
34 * de= 1234
35 * j= 45.123402
36 * ch= s
37 * s= 3.141500e+05
38 */
39
my question is, if assign or initialise the the value of float variable like above underlined marked red then it take the garbage value at output shown underlined bold. assigning variable in float with 0.0 also give garbage value at other precision value.