#include<stdio.h>
int main()
{
int x,y,z;
x=y=z=1;
++x||++y&&++z;
printf(“%d\t%d\t%d\n”,x,y,z);
return 0;
}
#include<stdio.h>
int main()
{
int x,y,z;
x=y=z=1;
++x||++y&&++z;
printf(“%d\t%d\t%d\n”,x,y,z);
return 0;
}
here x is preincremented first so x=2
there is || operation.anything ORed with 1 is 1.Hence compliler doesnt evaluate further expression.so y & z values remains unchanged