5 Responses to problem in assingment 01

1. himanshi says:

   June 28, 2012 at 1:22 am

   c first of all compiler will check the or operator as it has more priority than and gate then now in this case…it will execute from left
   1st process x=1
   then as soon as itll obtain or operator it ll incremt its value and then if it iz >0 it will directly give answr as 1…

   thanx

   Reply
2. himanshi says:

   June 28, 2012 at 1:23 am

   c first of all compiler will check the or operator as it has more priority than and gate then now in this case…it will execute from left
   1st process x=1
   then as soon as itll obtain or operator it ll incremt its value and then if it iz >0 it will directly give answr as 1… for the whole expression……….

   but for x=2,y=1,z=1
   thanx

   Reply
3. himanshi says:

   June 28, 2012 at 1:27 am

   im sorry actually i dint see properly…..
   actually x will incremented before encountering || operator………

   thnx

   Reply
4. sandeep.kumar says:

   June 28, 2012 at 12:41 pm

   ++x||++y&&++z

   x gets preincremented to 2.
   since logical or is evaluating to true in first expression(i.e. ++x) so rest of expression is not evaluated.

   and the result is 2,1,1

   Reply
5. hemant.kumar says:

   July 1, 2012 at 9:45 pm

   x=y=z=1;
   ++x (pre increement) it means x will be 2
   here ||(logical or)
   according to the compiler..it wont check further it it is true..so there will be no change in the values of y and z
   your output will be 2,1,1
   for instance…
   x=-1,y=1,z=1;
   then x,y,z will be 0,2,2
   logical or(||) -> if the first statement is true(1) then it wont check it further
   whereas logical(&&)–>it checks the whole statement.. here priority of these operators doesn’t matter..it goes from left to right

   Reply