#include<stdio.h>
int main ()
{
printf(“Program to print a pattern of stars.\n”);
int i1,i2,i3,val;
printf(“Enter a number:\n”);
scanf(“%d”,&val);
for(i1=0;i1<val;i1++)
{
/*for(i3=val;i3>i1;i3–)
{
printf(” “);
}*/
for(i2=0;i2<=i1;i2++)
{
printf(“*”);
}
printf(“\n”);
}
return 0;
}
I tried to print a pattern of stars using for loop. The problem i am facing with the logic is that i want to print the following pattern:
*
***
*****
******* /*i.e is odd number of stars to be printed in n number of lines ; Where n is specified by the user;*/ I wanted to print this pattern using for loop only.
anyone wid solution?
At the place of i1++ in first loop ,just apply i1=i1+2….
hope this will give u the correct one….
for(i2=0;i2<=i1;i2++)
{
printf(“*”);
}
look the for loop initialization you have initialized i2 with 0.
therefore you are getting one extra * at each line.
from 0 to i1 (updating according to upper llop) is the printing start's from 0 to i1.
so i suggest you to initialize i2 from 1 instead of 0.
check it out and reply me also
Shalini Singhal thanx for the help, it did solve my purpose for printing the star pattern as i wanted to print. Here is the successful program
The Current Print pattern for a value of 3 entered by the user gives:
"___* "
"__*** "
"_***** "
Replace"_" by space…
rahul1989… initializing i2 with 1 will produce a different result. The logic is to increment i1 by 2…
