Consider breaking down the problem into two main sections: the upper half and the lower half.
Upper Half Logic:
In the upper half, '*' characters need to start from the centralized column and spread outward.
Use a nested loop structure to iterate over the rows and columns.
The outer loop handles rows and runs from 0 to n-1, where n is the total number of rows.
The inner loop manages columns and is responsible for placing spaces before the '*' characters to ensure centralization.
Inside the inner loop, use conditions to determine when to print '*' characters. Specifically, the current row index is within a certain range around the centralized column.
Lower Half Logic:
For the lower half, adjust the logic accordingly.
The outer loop now runs in reverse order, starting from n-2 down to 0, as we've already handled the middle row in the upper half.
Similar to the upper half, use the inner loop to handle columns and adjust conditions to print '*' characters where needed.
Make sure to consider the change in conditions for the lower half to create a symmetric diamond pattern.
By dividing the problem into these two halves and carefully managing the conditions for '*' placement, you can construct a complete diamond pattern.