Doubt in do while loops.

nishant

int main()
{
char ch;
do
{
printf("Hello world\n");
printf("Do you want to print it again?Enter y for yes/n for no.\n");
scanf("%c",&ch);
}while(ch=='y');
}

When i run this program it print "Hello world" and "Do you want,,," statements 2 times then ask for entering the choice....
Give me reason why it happens????

saurabh2015ece

its do while loop.
first it will run the program and then check whether a condition is true or false.
if is it true it will execute statement again .

gkarya1990

char ch;
do
{
printf("Hello world\n");
printf("Do you want to print it again?Enter y for yes/n for no.\n");
scanf("%c",&ch);
}while(ch!='n');

this code is running as many times u want...just changing the condition in while at end.

gkarya1990

also when we press enter key then that is also taken as character and it matches ch with this character(i.e enter) and thus condition gets false.

preetamverma9076

What do you understand by while(0) and while(1) ?

mohammaduvais143

Let us talk about the differences between while(1) and while(0) in C language. The while(1) acts as an infinite loop that runs continually until a break statement is explicitly issued. The while(0) loop means that the condition available to us will always be false

mohammaduvais143

what will be the output of following code ?

#include<stdio.h>

int main()

{

int a = 0, i = 0, b;

for( i = 0; i < 5; i++)

{

a++;

continue;

}

return 0;

}

gaurav133232

the values will be :-

1

2

3

4

5

mdaliakbar

The output of following code is depend upon where your write printf. Before continue or after continue.

If before continue print a like printf("%d", a) ;
Now O/p is 1 2 3 4 5

If after continue print no output .

Doubt in do while loops.

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