What happens when the `execl()` function is called in user space, and how does it transition to kernel space? Include the role of `execve()` in your explanation.
When the user calls execl firstly it sets the arguments and parameters for the exec, then through glibc it transitions to execve as it is the only function that the kernel understands rest are considered as wrappers. The kernel then does the remaining of changing the process image and other tasks. The execve is basically a system call that sets a new environment variable for the process also the arguments are passed in an array.
