17. Basic `case` Statement

pravjot

17. Basic `case` Statement

Write a script that takes a day of the week as input and prints whether it is a weekday or weekend using a `case` statement.

vishutyagi45

#! /bin/bash

read -p "Enter a day of the week : " input_day

days="Monday Tuesday Wednesday Thursday Friday"

case "$days" in *"$input_day"*)

echo "$input_day is a weekday."

;;

*)

echo "$input_day is a weekend."

;;

esac

abhinandan2971verma

#! /bin/bash

read -p "Enter day of week " input

case $input in

'MONDAY'|'TUESDAY'|'WEDNESSDAY'|'THURSDAY'|'FRIDAY')

echo "IT IS WEEKDAY "

;;

'SATURDAY'|'SUNDAY')

echo "IT IS WEEKEND "

;;

*)

echo "WRONG CHOICE INPUT "

;;

esac

seerat1204

#! /bin/bash

read -p "Input a day: " day

case $day in
        monday)
                echo "Weekday."
                ;;
        tuesday)
                echo "Weekday."
                ;;
        wednesday)
                echo "Weekday."
                ;;
        thursday)
                echo "Weekday."
                ;;
        friday)
                echo "Weekday."
                ;;
        saturday)
                echo "Weekend."
                ;;
        sunday)
                echo "Weekend."
                ;;
esac

riteshtyagi725

#!/bin/bash

read -p "Enter the day of the week in complete form Eg:Monday: " day

case $day in

Monday|Tuesday|"Wednesday"|Thursday|Friday)

echo "It's a weekday."

;;

Saturday|Sunday)

echo "It's a weekend."

;;

*)

echo "It's an invalid day."

;;

esac

exit 0

17. Basic `case` Statement

17. Basic `case` Statement

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