NICE IMPLEMENTATION OF USAGE OF ARRAY OF POINTER

/*NICE PROGRAM TO PRESENT WORKING OF ARRAY OF POINTER*/

#include<stdio.h>

int main()

{

char *arr[]={"hello","hi","bye","bye"};//array of pointer..a array in which no. of strings in continues address may take place by leaving 1 space in between them..

//means arr[0]=hello    arr[1]=anu   arr[2]=hi   arr[3]=bye

////also *(arr+0)=hello *(arr+1)=anu *(arr+2)=hi *(arr+3)=bye

printf("arr=%s\n",*(arr+0));

printf("arg=%s\n",arr[2]);

char **p[]={arr+0,arr+1,arr+2,arr+3};//array of double pointer will have address of 1st array

printf("p=%s\n%s\n%s\n%s",*(*(p+0)),*(*(p+1)),*(*(p+2)),*(*(p+3)));//so pointer of double poiter will hold address of arrays of another pointer...& pointer to that will have value that array tht is string in this case...

char **s[]={&arr[0],&arr[1],&arr[2],&arr[3]};////array of double pointer will have address of 1st array

printf("s=%s\n%s\n%s\n%s",*(*(s+0)),*(*(s+1)),*(*(s+2)),*(*(s+3)));////so pointer of double poiter will hold address of arrays of another pointer...& pointer to that will have value that array tht is string in this case...

//printf("last=%s\n",*arr[2]);//this will give sementation fault

//char ***ptr[]={p[0],p[1],p[2],p[3]};

//printf("ptr=%s",***ptr);

return 0;

}