AN IMPLEMENTATION WHILE WANDERING INSIDE ASCII CHART

/*AN IMPLEMENTATION WHILE WANDERING INSIDE ASCII CHART*/

#include<stdio.h>

int main()

{

        char s[]={'a','b','c','\n','c','\0'};

        char *p,*str,*str1;

        p=&s[3];//

        printf("%c\n",*p);//bcz &s[3] contain address of new line character...//so while printing..// '\n' character operates....means "\n\n" means leave two lines....//directly..by printing nothing untill now//

        printf("akshat");//after leaving 2 lines,it should print akshat

        str=p;//put base address of p into another pointer str

        str1=s;//also address of s in str1...//

        printf("%d\n",*p);//*p has new line address..whose ascii value is 10.

        printf("%d\n",++*p);//bcz * has more priority than ++ operator,,,then *p=10 so increment of 10 is 11..means i m talking about ascii value is 11...

        printf("%c\n",*str1);//will str1=s...so *str1 will print a character at place str1[0]

        printf("%c\n",++*str1);//will print will increment ascii value of a character means prints b character

        printf("%c\n",++*str1-32);//will print b-32=B character.....bcz 97-65=32 98-66=32 99-67=32

//means ascii of lower letter- ascii of upper character is always 32..//

        printf("%d\n",++*p +  ++*str1-32);//so ++*p=11 ++*str1-32=ascii of B

//NOW ADDING 11+ASCIIoF(B)=ASCII OF CAPITAL(M)=77....SO PRINTING 77

//FINAL OUTPUT IS 77....//

//

        return 0;

}