AGAIN ANOTHER WAY OF GETING SUM OF SERIES..1+2+3+4...n/

//AGAIN ANOTHER WAY OF GETING SUM OF SERIES..1+2+3+4...n//

//TO FIND THE SUM OF N NATURAL NUMBERS//

#include<stdio.h>

int main()

{

        int sum=0,n,i;

        printf("ENTER THE NO:\n");

        scanf("%d",&n);

        sum=(n*(n+1))/2;//using formula n(n+1)/2....means 1(1+1)/2=2/2=1...2(2+1)/2=6/2=3...3(3+1)/2=3*4/2=6...ultimately in short formula...it will directly give u sum of n natural numbers..//

        for(i=1;i<=n;i++)

        {

                if(i!=n)

                        printf("%d+",i);

                else

                        printf("%d=%d\n",i,sum);

        }

        return 0;

}

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