A PROGRAM TO SEE *s++ HOW WILL THIS BEHAVE

/*A PROGRAM TO SEE *s++ HOW WILL THIS BEHAVE*/

#include<stdio.h>

#include<stdlib.h>

int main()

{

int i,*a,*s;

a=s=(int*)malloc(4*sizeof(int));

for(i=0;i<=4;i++)

*(a+i)=i*10;//0 10 20 30 40

printf("%d\n",*s++);//++ has more priority than *...s would have to ++ 1st & then it would have to get value at that address of s....but bcz it is post increment,,,,it will get value 1st ..complete its operation by printing that value & then increments address of s....so again when i printed ..value of s become the next value value than previous..//

printf("%d\n",*s);//will print value of incremented address//

return 0;

}

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