A PROGRAM TO COUNT NUMBER OF LETTERS IN ARRAY ACCORDING TO RANGE OF THEIR ASCII VALUES

/*A PROGRAM TO COUNT NUMBER OF LETTERS IN ARRAY ACCORDING TO RANGE OF THEIR ASCII VALUES*/

#include<stdio.h>

#define TRUE 1//MACROS REPRESENTING TRUE & FALSE

#define FALSE 0

int main()

{

        int i=0,hi=0,lw=0,in=0,done;

        done=TRUE;

        char c=0;//IS OF CHAR TYPE

        char arr[40];

        printf("ENTER THE STRING\n");

        scanf("%s",arr);//ENTER THE ARRAY//

        while((c=arr[i++])!='\0')

        {

                if(c<'0')//<48//IF CHARACTER WHOSE ASCII VALUE IS LESS THAN ASCII VALUE OF '0' THAT IS 48..//

                        lw++;//THEN THAT CHARACTER WILL BE COUNTED IN lw.variable.//

                else if(c>'9')//48+9=53//IF CHARACTER WHOSE ASCII VALUE IS MORE THAN ASCII VALUE OF '9'..THEN THAT LETTER IS COUNTED INTO hi variable//

                        hi++;

                else//else if  letter WHOSE ASCII VALUE is between '0' TO '9'...//

                        in++;//THEN THAT LETTER WILL BE COUNTED IN in variable..//

        }

        printf("lw=%d hi=%d in=%d\n",lw,hi,in);//print the count that how much characters in array have ascii value less than ..ascii value of 0...

//HOW MUCH LETTERS IN ARRAY HAVE ASCII VALUE MORE THAN ASCII VALUE THAN 9 LETTER..

//HOW MUCH LETTERS IN ARRAY HAVE ASCII VALUE IN BETWEEN 0 TO 9..//

        done=FALSE;

   return 0;

}

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