Operator Overloading using Friend Function

sumacangadi

This is an example of code that uses the friend function to make the (d3 = 10.1 + d1) '+' operator overloading permissible.

#include <iostream>

class MyClass {

private:

double value;

public:

MyClass(double val) : value(val) {}

// Overloaded addition operator as a friend function

friend MyClass operator+(const MyClass& obj, double constant)

{

return MyClass(obj.value + constant);

}

void display() const // Display function

{

std::cout << "Value: " << value << std::endl;

}

};

int main() {

MyClass d1(5.3);

MyClass d3 = 10.1 + d1; // Uses the overloaded + operator

d3.display();

return 0;

}

In this case, the operator+ is overloaded as a friend function, giving it access to the MyClass instances' private members. A new MyClass instance containing the sum of the value and the constant is returned by the friend function, which accepts a double constant and an instance of MyClass as operands.

Because of the overloaded operator's ability to add a constant (10.1) to an object of MyClass, a new instance (d3) can be created, making the equation d3 = 10.1 + d1 legal. After that, the display function is used to show the outcome.

usaidsyedmohd

mainly we are able to add a constant to an object as we declared the overloaded function as a friend function as we know friend function does not belong to any class.

Operator Overloading using Friend Function

Howdy, Stranger!

Categories