can anybody help why the value of a is printed 10 in below code?Thanks!

jacobgeorge2101

#include<stdio.h>

int main()
{
        union var
        {
                int a, b;
        };
        union var v;
        v.a=10;
        v.b=20;
        printf("%d\n", v.a);
        return 0;
}

sankalpnegi2310

@jacobgeorge2101

The output is 20, as expected for unions, and not 10, please check again.

ashutomar07

The output will be 20 as in unions the the newely assinged value will ovellap with previous one , previous value will be lost.

adeshagarwal02

@jacobgeorge2101

Union allows to store different data-type in same memory location.

The Output should be 20 because in above union one integer allotted to it therefore size of union will be 4 bytes when a =10 the value on the give address will be 10 when b=20 than 10 will be replaced by 20 so output would be 20

saurabh.hmr009

Yep the output will be 20 as once you assign a new value in a union , old value is destroyed.

jacobgeorge2101

ok got it,thanks!

can anybody help why the value of a is printed 10 in below code?Thanks!

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